intergration 發表於 13-6-2011 21:52:31

Pure math

本帖最後由 intergration 於 13-6-2011 21:55 編輯

1   a. Prove that a+b=b+a for any real nember a and b
   b. Prove that 1+2=3
         Hence,prove that 2+1=3

2   a. Prove that ab=ba for any real nember a and b
   bProve that (1)(2)=2
         Hence,prove that (2)(1)=2


                                                        HKALE Pure math 2013

just joking..

p445hkk20001 發表於 14-6-2011 14:34:09

好高深…
簡直唔係pure應該係大學以上既數

-終場ソ使者- 發表於 14-6-2011 18:51:31

施主,相信2013年的pure要在大學才再到

數學小子 發表於 20-6-2011 16:33:17

聽講1+1=2係要用1d高深既logic用set theory去prove

[H]bunbunbunbun 發表於 26-6-2011 07:35:25

Honestly there's not much to prove

Axioms of real numbers states that addition and multiplication are commutative
so a+b=b+a and ab=ba for all a,b real

also 1 is the identity of multiplication so by the axiom 1(2)=(2)(1)=2

prove 1+2=3 depends how much you can assume on the real number system
hell this is more like a philosophical question than an analysis question -,-
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